-7n^2+63n=0

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Solution for -7n^2+63n=0 equation:



-7n^2+63n=0
a = -7; b = 63; c = 0;
Δ = b2-4ac
Δ = 632-4·(-7)·0
Δ = 3969
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3969}=63$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(63)-63}{2*-7}=\frac{-126}{-14} =+9 $
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(63)+63}{2*-7}=\frac{0}{-14} =0 $

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